2. A basket contains 6 apples, 5 bananas, 4 oranges and 5 peaches. If you randomly choose one piece of fruit, eat it and then choose another, what is the probability that you would choose a banana and then an apple? (Enter your answer as a whole number percent.)

Answer:8% as a whole number percentStep-by-step explanation:Number of;Apples = 6Bananas = 5Oranges = 4Peaches = 5Total number of fruits in the basket = 6 + 5 + 4 + 5= 20Probability of picking a banana and then an apple = (5/20) × (6/19)= 30/380= 3/38=7.89% ≈ 8%