A 20ft by 40ft rectangular swimming pool is surrounded by a walkway of uniform width. If the total area of the walkway is 396 ft squared, how wide is the walkway

The width of the walkway is: 3 feetStep-by-step explanation:GivenLength of pool = 20 feetwidth of pool = 40 feetLet x be the width of the side walkwayThen the length with walkway will be: 20+2xWidth with walkway will be: 40+2xThen total area with walkway: [tex](20+2x)(40+2x)[/tex]so,[tex]Area\ with\ walkway - area\ of\ swimming\ pool=area\ of\ walkway\\(20+2x)(40+2x)-(20)(40)=396\\800+40x+80x+4x^2-800=396\\120x+4x^2=396\\4x^2+120x-396=0[/tex]Dividing both sides by 4[tex]x^2+30x-99=0\\x^2+33x-3x-99=0\\x(x+33)-3(x+33)=0\\(x+33)(x-3) = 0\\x-3=0 => x=3\\x+33=0 => x=-33[/tex]As the measurement of length cannot be negative, we will only consider the positive value.Hence, The width of the walkway is: 3 feetKeywords: Rectangle, AreaLearn more about area at:brainly.com/question/12973601brainly.com/question/13063819#LearnwithBrainly