a bridge is 38 feet above a river. how many seconds does it take a rock dropped from the bridge to pass by a tree limb that is 10 feet above the water?

Answer:it will take 1.32 secondsStep-by-step explanation:The height of the bridge above the river is 38 feetThe height of the tree limb above the river is 10 feetDisaster from the bridge to the tree limb = 38 - 10 = 28feet. The rock will travel 28feet before it passes the tree limb. To determine the time, we will apply Newton's equation of motion.h = ut + 1/2 ×gt^2where h = height of the rockt = time taken for the rock to fallu = initial velocity of the rock.g = acceleration of the object and it is also acceleration due to gravity.From the information given,h = 28 feetg = 32.2ft/s^2u = 0(velocity of the rock starts from 0 and increases as it keeps falling)28 = 0×t + 1/2 × 32.2 × t^228×2 = 32.2 × t^2t^2 = 56/32/2 = 1.74t = √1.74 = 1.32 seconds