a line with a slope of 5/3 passes through the point (10, -5). what is its equation in point slope​

The equation of line in point-slope form with slope 5/3 passing through the point (10-5) is:[tex]y+5 = \frac{5}{3}(x-10)[/tex]Step-by-step explanation:GivenSlope = m = 5/3Point = (x1,y1) = (10, -5)Point-slope form is:[tex]y-y_1 = m(x-x_1)[/tex]As the slope and point is already given, we only have to put the values in the equation to get the equation of required line:[tex]y-(-5) = \frac{5}{3}(x-10)\\y+5 = \frac{5}{3}(x-10)[/tex]Hence,The equation of line in point-slope form with slope 5/3 passing through the point (10-5) is:[tex]y+5 = \frac{5}{3}(x-10)[/tex]Keywords: equation of line, point-slope formLearn more about equation of line at:brainly.com/question/4401748brainly.com/question/4459688#LearnwithBrainly