a plane travels 800 miles in 5 hours with the wind. it went the same distance in 8 hours when flying aginst the wind. find the rate of the wind
Question
Answer:
x = planes speedy = wind speed
x +y = plane with wind
x-y = plane against wind
800 = 4(x+y) 4 hours to travel 800 miles with the wind
800 = 8(x-y) 8 hours to travel 800 miles against the wind
distribute the 2 formulas:
4x +4y = 800
8x -8y = 800
multiply 1st equation by 2 ( 8x +8y = 1600 )
add the 1st and 2nd equations:
8x + 8y = 1600
8x - 8y = 800
16x = 2400
divide both sides by 16
x = 2400 / 16
x = 150
use original 1st formula to solve for y ( wind speed)
4x +4y = 800
4(150) + 4y = 800
600 + 4y = 800
subtract 600 from each side:
4y = 200
divide both sides by 4
y = 200 / 4
y = 50
wind speed = 50 miles per hour
solved
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10 months ago
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