A population of cats has a population mean of μ = 12μ=12pounds and a population standard deviation of σ = 2.0σ=2.0pounds. The distribution of weights of these cats is fairly symmetrical. If you take a random sample of 100 cats from this population, what will be the resulting sampling distribution of x?

Answer:Normal (12, 0.20)Step-by-step explanation:Given that a population of cats has a population mean of [tex]\mu = 12pounds\\\sigma = 2 pounds[/tex] Also given that the distribution of weights of these cats is fairly symmetrical.Since sample size is large and a random sample of 100 cats are drawn from this population, we find thatthe mean of the sample would follow a normal distribution with mean =population mean and std deviation = population std dev/sqrt ni.e. Sampling distribution of X would be normal with mean = 12 poundsand std deviation = [tex]\frac{2}{\sqrt{100} } \\=0.20[/tex]