find in terms of p, the roots function f(x) = x^2 - 4px + 12p, where p is a positive constant

Question
Answer:
$x_{1,2}=\frac{-(-4p)\pm \sqrt{(-4p)^{2}-4\cdot 1\cdot 12p}}{2\cdot 1}$
$x_{1,2}=\frac{-(-4p)\pm 4\sqrt{p(p-3)}}{2\cdot 1}$
$x_{1}=\frac{-(-4p)+4\sqrt{p(p-3)}}{2\cdot 1},x_{2}=\frac{-(-4p)-4\sqrt{p(p-3)}}{2\cdot 1}$
$=2(p+\sqrt{p(p-3)})$
$=2(p-\sqrt{p(p-3)})$
$x=2(p+\sqrt{p(p-3)}),2(p-\sqrt{p(p-3)})$
solved
general 10 months ago 1291