if y=2cos(x/2) then d^2y/dx^2 =

Question

Answer:

We first need dy/dx.

dy/dx = -2sin(x/2)(1/2)

dy/dx = -sin(x/2)

We now find d^2y/dx^2.

d^2y/dx^2 = -cos(x/2)(1/2)

d^2y/dx^2 = -(1/2)cos(x/2)