Oneta writes an algebraic expression with three terms. The y-term has a coefficient of -3, and the x-term has a coefficient of 1. The expression does not have a constant term. Which expression could she have written? x - y2 - 3y x - 3y + 6 x + 3y2 + 3y x + 3y + 7

Answer:  The correct option is(A) [tex]x-y^2-3y.[/tex]Step-by-step explanation:  Given that Oneta writes an algebraic expression with three terms in which the y-term has a coefficient of -3, the x-term has a coefficient of 1 and there is n constant term.We are to select the correct expression she could have written.The coefficient of y term is -3, so one of the terms in the expression is -3y.The coefficient of x term is 1, so second term is x.And there is no constant term. Since options (B) and (D) contains constant terms, so they cannot be correct.Also, the coefficient of y in option (C) is 3, not -3. So, option (C) is also not correct.The only expression that matches with the given conditions is [tex]x-y^2-3y,[/tex] where the coefficient of y term is -3, the coefficient of x term is 1 and there is no constant term.Thus, (A) is the correct option.