Please help me out. pleaseeee.Hey guys, I have been having some trouble with this question related to quadratic formulas. Its a 3 part question, but I only want the first part done, so I can do the rest. Here is the question:3. A rocket is launched vertically from the ground with an initial velocity of 64 . (a) Write a quadratic function h(t) that shows the height, in feet, of the rocket t seconds after it was launched.Thank you so much in advance. I really appreciate it.
Question
Answer:
h = heightt = time
the formula for distance in a given time is - 1/2gt^2 where g is the acceleration due to gravity which is 32 ft/sec^2
so 1/2 of that would be -16t^2
then you would want to add the velocity of the rocket times the amount of time which is 64t
that gives the final equation as: h(t) = -16t^2 + 64t
solved
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10 months ago
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