PLEASE PLEASE HELP ME!!!!!! DO NOT DO IT FOR POINTS! I GENUINELY NEED HELP! 1. Rewrite each expression by combining like terms. 8 p q − 3 p q and 2 m − 3 m + 42. A carnival costs $10.50 to enter plus an additional $3.50 per ticket for rides and food.Write an algebraic expression to represent the total cost for a visit to the carnival. Let n represent the number of tickets purchased.​​What is the total cost to visit the fair if you purchase 20 tickets? Explain your reasoning.3. Which expression is equivalent to 8−4(x−6)/4?A. x+32B. −x+8C.−4x−8D. x−7/2THERE WILL BE TOMORROW!!THANK YOU SO SO SO MUCH!!

Answer:1. Expression can be rewritten as [tex]5pq[/tex] and [tex]-m+4[/tex]2. The expression for total cost for a visit = [tex]\$10.50+ \$3.2n[/tex] and the Total Cost to visit the fair for 20 tickets is [tex]\$80.50[/tex]3.  B.  [tex]-x+8[/tex]Step-by-step explanation:1. Solving for first QuestionGiven expression are [tex]8pq-3pq[/tex] and [tex]2m-3m+4[/tex]Solving equation we get,[tex]8pq-3pq=5pq\\2m-3m+4=-m+4[/tex]Expression can be rewritten as [tex]5pq[/tex] and [tex]-m+4[/tex]2. Solving for 2 QuestionGiven Fixed cost of carnival = [tex]\$ 10.50[/tex]Additional Cost per ticket for food and ride  = [tex]\$ 3.50[/tex][tex]n[/tex] represents number of tickets.Total cost to visit carnival = Fixed cost of carnival + Additional Cost per ticket for food and ride[tex]\times[/tex] Number of tickets = [tex]\$ 10.50+\$ 3.50n[/tex]algebraic expression to represent the total cost for a visit to the carnival = [tex]\$ 10.50+\$ 3.50n[/tex]Now Number of tickets sold n  = 20Total cost to visit carnival= [tex]\$ 10.50+\$ 3.50n= \$ 10.50+\$ 3.50\times20= \$ 10.50+\$ 70 =\$ 80.50[/tex]Total Cost to visit the fair for 20 tickets is [tex]\$80.50[/tex]3. Solving for 3 question.Given : [tex]\frac{8-4(x-6)}{4}[/tex]Solving Above equation we get:[tex]\frac{8-4(x-6)}{4}= \frac{4(2-x+6)}{4}=-x+8[/tex]Hence the answer is  B.  [tex]-x+8[/tex]