sunil and luisa went to get a double sccop of ice cream each. SUnil bought his ice cream from a shop that had three different flavours: blueberry, vanila and chocolate. He could therefore choose from six different combinations. BB, BV, BC, VV, VC, CC. Luisa when to another shop which had 10 different flavours. From how many different combinations could she choose?

Luisa went to a shop with 10 different flavors. She's also getting a double scoop of ice cream. To find out how many different combinations she could choose from, we need to determine the number of ways she can choose two flavors out of the 10 available flavors. This is a combination problem, and the formula for calculating combinations is: $$ C(n, r) = \frac{n!}{r!(n - r)!}$$ where n is the total number of items to choose from and r is the number of items to be chosen. In this case, Luisa is choosing 2 flavors out of the 10 available flavors, so n = 10 and r = 2. Plug these values into the combination formula: $$ C(10, 2) = \frac{10!}{2!(10 - 2)!} = \frac{10 \times 9}{2 \times 1} = 45$$ Luisa can choose from 45 different combinations of flavors for her double scoop of ice cream.