Suppose that circles A and B have a central angle measuring 40°. Additionally, circle A has a radius of 5/2 ft and the radius of circle B is 9 /2 ft. If the measure of the sector for circle A is 25/36 π ft2, what is the measure of the sector for circle B? A) 2 9 π ft2 B) 4 9 π ft2 C) 9 4 π ft2 D) 9 2 π ft2

Question

Answer:

The measure of the sector of circle B is given by:
A=θ/360πr²
But
θ=40°
r=9/2 ft
thus
A=40/360×π×(9/2)²
A=(9π)/4 ft²

Answer: C] (9π)/4 ft²