The side lengths of triangle ABC are written in terms of the variable p, where p ≥ 3. Triangle A B C is shown. Side A B has a length of 4 p minus 1, Side B C has a length of 3 p, and side A C has a length of p + 4. Which is correct regarding the angles of the triangle? mAngleA > mAngleC > mAngleB mAngleB > mAngleA > mAngleC mAngleC > mAngleA > mAngleB mAngleC > mAngleB > mAngleA

Answer:Angle C > Angle A > Angle B Step-by-step explanation:In Δ ABC, the sides AB = 4p - 1, BC = 3p and CA = p + 4, where p ≥ 3. Assume, p = 3, then AB = 11 units, BC = 9 units and CA = 7 units. We know, the angle of a triangle is larger for the larger length of the opposite side. So, Angle C > Angle A > Angle B  Therefore, option c is correct. (Answer)