What are the solutions to the equation?a^2 −10a + 25 = 49Enter your answers in the boxes.a1 = a2 =
Question
Answer:
Subtract 49 from both sides to get equation into [tex]a x^{2} +bx+c=0[/tex] form:[tex] a^{2} -10a-24=0[/tex]
Then factor:
[tex](a-12)(a+2)=0[/tex]
Solutions corresponding to these factors are [tex]a=12[/tex] and [tex]a=-2[/tex].
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10 months ago
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