Let a be the leg of a 45 ° -45 ° -90 ° Triangle. sin 45 ° =- sec 45 ° =- cos 45 ° =frac csc 45 ° =frac tan 45 ° =- cot 45 ° =frac

Question
Let a be the leg of a 45 ° -45 ° -90 ° Triangle. sin 45 ° =- sec 45 ° =- cos 45 ° =frac csc 45 ° =frac tan 45 ° =- cot 45 ° =frac
Answer:
Let a be the leg of a 45 ° -45 ° -90 ° Triangle. sin 45 ° =- sec 45 ° =- cos 45 ° =frac csc 45 ° =frac tan 45 ° =- cot 45 ° =frac 65105aecc5734.webp
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algebra 10 months ago 7493