A coffee pot in the form of a circular cylinder of radius 2 in. is being filled with water flowing at a constant rate. If the water level is rising at the rate of 0.9 in./s, what is the rate (in in3/s) at which water is flowing into the coffee pot? (Round your answer to one decimal place.)

Answer:11.3 in^3/sStep-by-step explanation:Water level rising rate = 0.9 in/sThe cross-sectional area of the coffee pot is given by;[tex]A= \pi r^2\\A = \pi 2^2\\A= 12.5664\ in^2[/tex]The rate at which water is flowing into the coffee pot is given by the product of the cross-sectional area by the rate at which the level rises:[tex]R_{v} = 12.5664\ in^2 * 0.9\ in/s \\R_{v} = 11.3 \ in^3/s[/tex]Water flows into the coffee pot at 11.3 in^3/s