At each scooter's top speed brand a goes 2 miles per hour faster than brand b. After traveling at its top speed for 3 hours brand a scooter traveling 40.2
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Question is Incomplete, Complete question is given below.Brand A scooter has a top speed that goes 2 miles per hour faster than Brand B. If after 3 hours, Brand A scooter traveled 40.2 miles at its top speed, at what rate did Brand B scooter travel at its top speed if traveled the same distance? Write an equation to determine the solution.Answer:The equation to determine solution is [tex]40.2 = (2+x)3[/tex].Brand B will travel at a rate of 11.4 miles per hour.Step-by-step explanation:Given:Distance traveled by brand A = 40.2 milestime required to cover distance = 3 hours.Brand A scooter has a top speed that goes 2 miles per hour faster than Brand BLet brand B scooter has a top speed of xHence Brand A scooter has a top speed will be [tex]2 + x[/tex]Now we know that Distance traveled by brand A scooter is equal to Brand A scooter top speed multiplied by time reuired to cover the distance by brand A [tex]40.2 = (2+x)3[/tex].Hence the equation to determine solution is [tex]40.2 = (2+x)3[/tex]Now we will find the rate of brand B by solving the same we get.[tex]40.2 = 6+3x\\3x = 40.2-6\\3x = 34.2\\x= 11.4 \ m/h[/tex]Hence Brand B will travel at a rate of 11.4 miles per hour.
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