Clair has 60 yd of fence with which to build a rectangular pig sty. What is the maximum area she can enclose? Enter your answer in the box.

Answer: Maximum area would be 225 sq. yard.Step-by-step explanation:Since we have given thatPerimeter of rectangular pig sty = 60 ydAs we know the formula for "Perimeter ":[tex]60=2(l+b)\\\\\dfrac{60}{2}=l+b\\\\30=l+b[/tex]Since we need the maximum area she can enclose:Square with same perimeter would enclose maximum area than the rectangle.For this we assume l=b.So, it becomes,[tex]30=l+l\\\\30=2l\\\\\dfrac{30}{2}=l\\\\15\ yd=l[/tex]So, Maximum area would be [tex]Side\times Side\\\\=Side^2\\\\=15^2\\\\=225\ sq.\ yard[/tex]Hence, the maximum area would be 225 sq. yard.