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Answer:Step-by-step explanation:Property of the perpendicular lines,If the two lines [tex]L_1[/tex] and [tex]L_2[/tex] having slopes [tex]m_1[/tex] and [tex]m_2[/tex] are perpendicular to each other,Then [tex]m_1\times m_2=-1[/tex]Equation of line [tex]L_1[/tex] → y = 3x + 5 ------(1)Equation of line [tex]L_2[/tex] → 6y + 2x = 1 ------- (2)Slope of line [tex]L_1[/tex],[tex]m_1=3[/tex]Slope of line [tex]L_2[/tex],6y + 2x = 16y = -2x + 1[tex]y=-\frac{2}{6}x+\frac{1}{6}[/tex][tex]y=-\frac{1}{3}x+\frac{1}{6}[/tex]Therefore, [tex]m_2=-\frac{1}{3}[/tex]By using the property of perpendicular lines,[tex]m_1\times m_2=3\times (-\frac{1}{3} )[/tex]               [tex]=-1[/tex]Therefore, both the lines are perpendicular.