what is the awnser to the circled equations?​

Answer:[tex]y = - \frac{1}{3}x - 1[/tex]Step-by-step explanation:We have to write an equation of a line which  passes through the given point (-9,2) and is perpendicular to the given straight line y = 3x - 12 ........... (1) Now, equation (1) is in the slope-intercept form and the slope of the line is 3. Let, m is the slope of the required line. So, 3m = -1 {Since, the product of the slopes of two perpendicular straight lines is -1} ⇒ [tex]m = - \frac{1}{3}[/tex] Therefore, the equation of the required line in slope intercept form is  [tex]y = - \frac{1}{3} x + c[/tex] {Where c is a constant} Now, this above equation passes through the point (-9,2) point. So, [tex]2 = -  \frac{1}{3} \times (-9) + c[/tex] ⇒ 2 = 3 + c ⇒ c = - 1  Therefore, the equation of the required straight line is [tex]y = - \frac{1}{3}x - 1[/tex] (Answer)