Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula?

The correct answer is:[tex]x=\frac{1\pm \sqrt{(-1)^2-4(1)(-2)}}{2(1)}[/tex]Explanation:The Quadratic Formula is[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex], where a, b and c are the coefficients of a quadratic equation written in standard form, or 0=ax²+bx+c.This means that first, we need to make our equation equal 0.We have -2 = -x + x² - 4To make this equal 0, we must cancel the -2.  We do this by adding 2:-2+2 = -x + x² - 4 + 20 = -x + x² - 2Now we write this in standard form.  This means the x² term must come first, then the x term, then the constant:0 = x²-x-2This makes a = 1, b = -1 and c = -2.  We then plug this into the quadratic formula.